If earth has a mass 9 times and radius 4 timesOutward from the Sun, the planets are Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus, and Neptune, followed by the dwarf planet Pluto. Jupiter's diameter is about 11 times that of the Earth's and the Sun's diameter is about 10 times Jupiter's. Pluto's diameter is slightly less than one-fifth of Earth's.Mass of the Earth, m = 6 x 10 24 kg Distance between the Sun and the Earth, r = 1.5 x 10 11 m Gravitational force between two masses is given by, F = $$\frac{\mathrm{GMm}}{r^{2}}$$ ∴ F = 3.6 x 10 22 N. Question 2. A planet x has a mass 2 times and radius 3 times that of the Earth.If earth has a mass 9 times and radius 4 times than that of a planet "P". Calculate the escape velocity at the planet 'P' if its value on earth is 11.2 kms -1. Ans. = 7.47 km/sec; At what height from the surface of the earth will the value of 'g' be reduced by 36% of its value at the surface of earth. Ans.11. A year on Mars equals 1.88 Earth years. If the earth is 1.5x10 11 m from the sun, use Kepler's third law to determine how far Mars is from the sun. T M T E 2 = r M r E 3 r M 3 = T M 2r E 3 T E 2 = ( )1.88yrs2(1.5x1011m)3 (1yr)2 r M =2.28x1011m 12. A hypothetical planet has a radius 2.5 times that of Earth, but has the same mass. What is the ...At top of Everest, d = 6.4 x 106 + 8850 = 6.40885 x 106 m So, the force is (6.4/6.40885)2 = 0.997 as much eg. If you weigh 200-lb here, then you'll weigh 199.4-lb on Mt Everest. i.e. g = 9.8 N/kg that we defined earlier, is just g = Gm earth/R earth 2 . Ordinary distances on earth are so small c.f. radius of earth, that their distance to ...If the Earth has a mass 9 times and a radius twice of the planet Mars, calculate the minimum velocity required by a rocket to pull out of the gravitational force of Mars. Escape velocity on the surface of Earth is 11.2 km s-1. Answer: Let Mm and be the mass and radius of Mars, and M, R = mass and radius of Earth.Its diameter is about 12,700 kilometers (7,900 miles), and its mass is about 5.97×10 24 kilograms (6.58×10 21 tons). In contrast, Jupiter, the largest planet in the solar system, has a diameter of 143,000 kilometers (88,850 miles), and its mass is about 1,898×10 24 kilograms (2093×10 21 tons). Earth is an oblate spheroid.Here we report observations of the transiting planet GJ 1214b, which has a mass of 6.55M[symbol:see text]), and a radius 2.68 times Earth's radius (R[symbol:see text]), indicating that it is intermediate in stature between Earth and the ice giants of the Solar System. We find that the planetary mass and radius are consistent with a composition ...For example: Joe Average has a mass of 63.5 kg and he feels a force of gravity on the Earth = 63.5 kg × 9.8 m/s 2 = 623 kg m/s 2 = 623 N. His weight is 623 N. The other value in the preceding equation, 9.8 m/s 2, is the acceleration due to gravity close to the Earth's surface. Joe Average's weight at other places in the universe will be ...So we can relate the force on the surface of Saturn to the force on the surface of the Earth. It will change like: m Saturn / R 2 Saturn. Since Saturn has a mass that is 95 times the mass of the Earth and a radius that is 9.4 times the radius of the Earth we expect the surface gravity to be 95/(9.4) 2 = 1.1 times the Earth'sJupiter is the largest of the nine planets, more than 10 times the diameter of Earth and more than 300 times its mass. In fact, the mass of Jupiter is almost 2.5 times that of all the other planets combined. Being composed largely of the light elements hydrogen and helium, its mean density is only 1.314 times that of water.For example, Gliese 581g has 2.6 times Earth's mass and 1.4 times its radius, for a gravity 1.33 times that of ours. Source: Habitable Exoplanet Encyclopedia . Most of the masses and radii are ...You can view the weight as a measure of the mass in kg times the intensity of the gravity field, 9.8 Newtons/kg under standard conditions. Data can be entered into any of the boxes below. Then click outside the box to update the other quantities. At the Earth's surface, where g=9.8 m/s 2:Correct answers: 1 question: The planet Saturn has a mass 95.2 times that of the earth and a radius 9.47 times that of the earth. Find the escape speed for objects on the surface of Saturn. Answer in units of km/s.is mrs meyers safeTextbook solution for University Physics (14th Edition) 14th Edition Hugh D. Young Chapter 9 Problem 9.86P. We have step-by-step solutions for your textbooks written by Bartleby experts!Posted on 9 November 2021 by lets tokmak Suppose our sun had 4 times its present mass but the earth orbited it at the same distance as it suppose our sun had 4 times its present mass but the earth orbited it at the same distance as it presently does. what would be the length of the year on the earth under those conditions?Area x T 4, not just T 4. or Luminosity ~ (Radius) 2 x T 4. So the extra factor of 1,000,000 = 10 6 represents an increased area, or a radius increase of 1,000 that is, type O has a radius 1000 times the radius of type M. The above equation can be rearranged to derive an equation for the radius: (Radius) 2 ~ Luminosity / T 4 orA satellite of mass 1000 kg is in circular orbit about Earth. The radius of the orbit of the satellite is equal to two times the radius of Earth. (a) How far away is the satellite? (b) Find the kinetic, potential, and total energies of the satellite.4. X ICÑ Où X X 2. The ISS follows an orbit that is, on average, 450 km above the surface of Earth. Determine (a) the speed of ISS and (b) the time for one orbit. 3. Denve an expression forthe radius of a satellite's orbit around Earth in terms of the period of revolution, the universal gravitation constant, and Earth's mass. 4.The above equation demonstrates that the acceleration of gravity is dependent upon the mass of the earth (approx. 5.98x10 24 kg) and the distance (d) that an object is from the center of the earth. If the value 6.38x10 6 m (a typical earth radius value) is used for the distance from Earth's center, then g will be calculated to be 9.8 m/s 2 .3. a) Jupiter is about 5 times farther away from the Sun than the Earth is, and has about 300 times the mass of the Earth. Compare the gravitational force between Jupiter and the Sun to the gravitational force between the Earth and the Sun. Part 1: Data Masses: M Jup = 300 M EarMay 14, 2021 · = 4/9 x g. Hence, the values of g decreases by 4/9 times. Problem 5: A planet has a radius and mass are half those of the earth. Find the acceleration due to gravity on the planet? Solution: Given that, The radius of the planet, r p = 2r. The mass of the planet, M p = 2M. The formula to calculate the acceleration due to gravity of the planet, g ... This shorter time would decrease the probability of observing such a star by ~1/4. On the other hand, lower-mass 55M ⊙ stars may be roughly four times as numerous as 100M ⊙ stars, depending on ...anime mugen apkpureMar 29, 2022 · Just slightly larger than nearby Venus, Earth is the biggest of the four planets closest to the Sun, all of which are made of rock and metal. The name Earth is at least 1,000 years old. All of the planets, except for Earth, were named after Greek and Roman gods and goddesses. However, the name Earth is a Germanic word, which simply means “the ... An astronaut of mass $$\text{70}$$ $$\text{kg}$$ on Earth lands on a planet which has half the Earth's radius and twice its mass. Calculate the magnitude of the force of gravity which is exerted on him on the planet.| If earth has a mass nine times and radius twice that of the planet mars, calculate the maximum velocity required by a rocket to escape from the gravitational field of mars. Take escape velocity on the earth's surface to be 11.2 km/s. A. 5.279 km/s B. 23.75 km/s C. 9144 km/s D. 3.865 km/s29. Planet X has a radius 4 times that of Earth and the acceleration due to gravity at the surface of planet X is 4.9 m/s2. The mass of Planet X compared to Earth's mass is a. 16 times b. 8 times c. 4 times d. 2 times e. the sameUse the standard values of g, R E R E, and Equation 13.2 to find the mass of Earth. Estimate the value of g on the Moon. Use the fact that the Moon has a radius of about 1700 km (a value of this accuracy was determined many centuries ago) and assume it has the same average density as Earth, 5500 kg/m 3 5500 kg/m 3. StrategyMay 12, 2017 · UUID. d9f1aacb-36ff-11e7-9770-bc764e2038f2. The Astronomy Calculator includes functions that are useful for studying astronomy. Formulae are organized in different tabs to the right as follows: Kepler's 3 rd Law formula T² = (4π • R³)/ (G • M) (M) - mass of the system . (T) - period of the orbit. (R) - separation distance between the two ... Mass of the Earth, m = 6 x 10 24 kg Distance between the Sun and the Earth, r = 1.5 x 10 11 m Gravitational force between two masses is given by, F = $$\frac{\mathrm{GMm}}{r^{2}}$$ ∴ F = 3.6 x 10 22 N. Question 2. A planet x has a mass 2 times and radius 3 times that of the Earth.The escape velocity from the earth's surface is 11 km/sec. A certain planet has a radius twice that of the earth but its mean density is the same as that of the earth. The value of the escape velocity from this planet would be Option 1) 22 km/sec Option 2) 11 km/sec Option 3) 5.5 km/sec Option 4) 16.5 km/secThe mass increases with the cube of the radius so a planet of 2 times earths radius would have a mass of 2³ = 8 times our mass, other things being equal which they aren't density being the ...The escape speed depends on the mass of Earth, radius of Earth, and the universal gravitational constant. However, it does not depend on the mass of the rocket. Chapter 12 Gravity Q.103IP Suppose the Earth is suddenly shrunk to half its present radius without losing any of its mass.Transcribed Image Text: 3.10 An earth-orbiting satellite has a period of 14 h and a perigee radius of 10,000 km. At time t = 10 h after perigee passage, determine (a) The radial position. (b) The speed. (c) The radial component of the velocity.pe on megger testerA satellite of mass 1000 kg is in circular orbit about Earth. The radius of the orbit of the satellite is equal to two times the radius of Earth. (a) How far away is the satellite? (b) Find the kinetic, potential, and total energies of the satellite. If the mass of Mars is 0.107 times that of Earth, and its radius is 0.530 that of Earth, estimate the gravitational acceleration g at the surface of Mars.(gearth = 9.80 m/s2) A)2.20 m/s2 B)3.73 m/s2 C)4.20 m/s2 D)5.50 m/s2Then, we are to consider a planet with mass five times that of Earth and radius three times larger. So the g for this planet is: g planet = (G(5M)/(3R) 2 ) = 5GM/9R 2 = (5/9)(GM/R 2 ), where M and R are the mass and radius of the Earth.Example: If one second passes outside the influence of the star's gravity, how much time passes on the surface of the star? Let's use the mass and radius of a super dense neutron star, like PSR J0348+0432. $$M = 4.02 \times 10^{30} \, \mathrm{ kg} \quad \quad r = 13 \, \mathrm{km}$$ solution $$\Delta t_0 = \Delta t_f \sqrt{1 - \left( \frac{2GM}{rc^2} \right) }$$  \Delta t_0 = 1 \sqrt{1 ...The radius of orbit indicates the distance which the satellite is from the center of the earth. Now that the radius of orbit has been found, the height above the earth can be calculated. Since the earth's surface is 6.37 x 10 6 m from its center (that's the radius of the earth), the satellite must be a height of. 4.23 x 10 7 m - 6.37 x 10 6 m ... Let us consider a planet such that mass of the planet is equal to 4 times the mass of the earth. M p = 4M. Radius of the planet is equal to 3 times the radius of earth. R e = 3 R. Then, acceleration due to gravity on this planet (g p) is. g p = G ∗ (4 M) 3 R 2 = 4 9 G M R 2.....(2) Dividing equation (2) by equation (1), we get. g p g e = 4 9 ...where g = gravity, G is the universal constant, M is mass, and r is the radius of the planet. earths mass is about 5.937e24 kg. and radius is about 6.371e6 km keep in mind that the earth is not ...Taking the age of Earth to be about $4\times 10^{9}$ years and assuming its orbital radius of $1.5 \times 10^{11} \textrm{ m}$ has not changed and is circular, calculate the approximate total distance Earth has traveled since its birth (in a frame of reference stationary with respect to the Sun).Doubling the mass of the Earth would double your weight, since gravitational force is directly proportional to mass, but doubling the radius (which doubles if the diameter doubles) would decrease your weight by a factor of 1/4, since gravitational force is inversely proportional to the square of the radius.Mass of earth m 1 =6 × 10 24 kg. Mass of the object m 2 = 1 kg. Radius of the earth =6.4 × 10 6 m. Universal gravitational constant G = 6.67 x 10-11 Nm 2 kg-2. By applying universal law of gravitation: - F = (G m 1 m 2 /r 2) = (6.67 x 10-11 x 6 × 10 24 x 1)/ (6.4 × 10 6) 2. F = 9.8 N. Question 4. The earth and the moon are attracted to each ...Orbiting Earth at an average distance of 384,400 km (238,900 mi), or about 30 times Earth's diameter, its gravitational influence very slowly lengthens Earth's day and is the main driver of Earth's tides. The Moon's orbit around Earth has a sidereal period of 27.3 days. The Sun has 333,000 times more mass than the Earth. And Jupiter has 318 times more mass. But then there are some less massive objects too. Mars has only 11% the mass of the Earth.Q: If Earth has mass nine times and radius twice that of the planet mars, calculate the velocity required by a rocket to pull out of the gravitational force of Mars. Take escape speed on surface of Earth to be 11.2 Km/s. Sol: Here, M e = 9M m, and R e = 2R m. v e (escape speed on surface of Earth) = 11.2km/stikka roughtech emberThe distance between the object and the planet or earth is taken as the radius of the earth or planet in this case and the mass is the product of volume and density. Complete step by step answer: The density of a given planet is twice the density of earth but the acceleration due to gravity on the surface of this planet is the same as that on ...The mean radius of the orbit of a satellite is 4 times as great as that of the parking orbit of the earth. Then its period of revolution around the earth is 64305024227.2k views asked Jun 19, 2019 in Physics by Sweety01 (70.2k points) If earth has a mass 9 times and radius 4 times than that of a planet 'P'. Calculate the escape velocity at the planet 'P' if its value on earth is 11.2 kms-1. gravitation class-11 1 Answer ← Prev Question Next Question → Find MCQs & Mock Test Free JEE Main Mock TestThe mass of the moon is 1 / 81 of earth's mass and its radius 1 / 4 that of earth. If the escape velocity from the earth's surface is 11.2 km / s,its value for themoon....A. 0.5 km / sB. 5.0 km / sC. 0.14 km / sD. 2.5 km / sMars has a diameter of approximately $0.5$ times that of earth and mass is $0.1$ times that of earth. The surface gravitational field strength on mars as compared to that of earth is a factor of A. $0.1$ B. $0.2$ C. $2.0$ D. $0.4$A satellite of mass 1000 kg is in circular orbit about Earth. The radius of the orbit of the satellite is equal to two times the radius of Earth. (a) How far away is the satellite? (b) Find the kinetic, potential, and total energies of the satellite.how long is the wait for safpThe earth has a radius of approximately 6300 kilometers. Find the total mass of the earth. The volume of a sphere is $$V=\frac 43 \pi R^3\text{.}$$ Find the volume of the earth, and calculate the average density of the earth. (Average density is the total mass divided by total volume.)The sun has a mass of 1.99x10 30 kg so this neutron star has a mass five times that: 5(1.99x10 30 kg) = 9.95x10 30 kg Its radius is 10 km or 10,000 m Now we just plug into our formulaIf earth has a mass nine times and radius twice that of the planet mars, calculate the maximum velocity required by a rocket to escape from the gravitational field of mars. Take escape velocity on the earth's surface to be 11.2 km/s. the Earth is about six times larger than that at the surface of the Moon, and the fact that the Earth's radius is about four times the Moon's radius, determine how the mass of the Earth compares to the mass of the Moon. = 2. Gm g r ⇒ r. 1 2. g. 1 / m. 1 = r. 2 2. g. 2 / m. 2. m. 2 / m. 1 = (r. 2 / r. 1) 2 (g. 2 / g. 1) = (1/4) 2 (1/6) = 1 ...An Earth mass (M E or M 🜨, where U+1F728 is the standard astronomical symbol for the Earth), is a unit of mass equal to the mass of the planet Earth.The current best estimate for the mass of the Earth is M 🜨 = 5.9722 × 10 24 kg, with a standard uncertainty of 6 × 10 20 kg (relative uncertainty 10 −4). The recommended value in 1976 was (5.9742 ± 0.0036) × 10 24 kg.1. Star Freddy has a radius that is 10 times smaller than the Sun's, while its temperature is 4 times greater. How does Freddy's luminosity compare to that of the Sun? Solution: Put the values right into the formula - L = R 2 T 4 L = (1/10) 2 4 4 (since it is 10 times smaller, it has to go in as 1/10) L = 1/100 x 256 L = 256/100 = 2.56Q: If Earth has mass nine times and radius twice that of the planet mars, calculate the velocity required by a rocket to pull out of the gravitational force of Mars. Take escape speed on surface of Earth to be 11.2 Km/s. Sol: Here, M e = 9M m, and R e = 2R m. v e (escape speed on surface of Earth) = 11.2km/sA hypothetical planet has a radius 2.3 times that of Earth. but has the same mass. What is the acceleration due to gravity near its surface? .Interested in T...Expert Answer Given, mass of planet is m = 0.9M ( where M is mass of earth) M = 5.972*10^24 kg radius of planet is r = 1.2R (where R is radius of the planet) R = 6371000 m so let mass of least mas … View the full answerJul 09, 2019 · If the earth has a mass nine times and radius twice that of the planet Mars. Given escape speed on the surface of Earth is 11.2 km s^(-1). asked Oct 31, 2021 in Physics by HimanshuJain ( 91.0k points) The escape velocity for the earth is 11.2 km/s. The mass of another planet 100 times mass of earth and its radius is 4 times radius of the earth. The escape velocity for the planet is the mass of Vesta in units of the mass of the Earth the volume of Pluto in units of the volume of the Earth a) the mass of Jupiter: M Jupiter = 1.90 x 10 27 gm x (1 M earth / 5.98 x 10 24 gm) = 317.8 M earth b) the diameter of Saturn: D saturn = 120,660 km x (1 D earth / 12,756 km) = 9.46 D earth c) the mass of the Moon:Mass of the Earth, m = 6 x 10 24 kg Distance between the Sun and the Earth, r = 1.5 x 10 11 m Gravitational force between two masses is given by, F = $$\frac{\mathrm{GMm}}{r^{2}}$$ ∴ F = 3.6 x 10 22 N. Question 2. A planet x has a mass 2 times and radius 3 times that of the Earth.Size, Mass and Density: Earth's has a mean radius of 6,371 km (3,958.8 mi), and a mass of 5.97 × 10 24 27 kg. In short, Jupiter is almost 11 times the size of Earth, and just under 318 times as ...A hypothetical planet has a mass of one-half that of the earth and a radius of twice that of the earth. What is the acceleration due to gravity on the planet in terms of g, the acceleration due to gravity at the surface of the earth? A) g B) g/2 C) g/4 D) g/8 E) g/16Planet X has the same mass as the Earth, but 1/2 the radius. (Planet X is more dense than the Earth). Suppose your mass is some 55 kg, so your weight at the sea level on Earth is about 120 lb.The Earth, orbiting the Sun, plays the same role as the probe sent to orbit Cygnus X-1. From this, it follows that: The equation can be rearranged to solve for the mass of the Sun, M, by canceling the mass of the Earth, m, from both sides, and the orbital radius of the Earth, r.ak rear sling1) a. A hypothetical planet has 4 times the radius of Earth and 8 times its mass. Determine the value of the acceleration of gravity on the surface of that planet. b. Determine how fast a satellite must orbit to maintain an orbit at a distance from the Earth's surface equal to 2 times the Earth's radius. c.In other words, the mass of the Earth is about 81 times that of the Moon. Radius. Radius of Earth: R E = 6.371*10 6 m. Radius of Moon: R M = 1738*10 3 m. R E /R M = 6.371*10 6 /1738*10 3 = 3.66 (R E /R M) 2 = 13.4. R E 2 = 13.4*R M 2. In other words, the square of the Earth's radius is about 13.4 times that of the Moon. Gravity. The ...If earth has amass 9 times and radius 4 times than that of a planet 'P'. Calculate the escape velocity of the planet P if its value on earth is 11.2 km/s. Kranav Sharma, Meritnation Expert added an answer, on 14/12/13 The escape velocity is given as v= [2GM/R] 1/2 now, for earth v e = [2GM e /R e] 1/2 or v e = 11.2km/s for planet9. The planet Venus requires 225 days to orbit the sun, which has a mass M = 1.99 1030 kg, in an almost circular trajectory. Calculate the radius of the orbit and the orbital speed of Venus as it circles the sun. 10. The Solar Maximum Mission Satellite was placed in a circular orbit about 150 mi above Earth.Dec 11, 2012 · r / m) = 8.9 m/s Solve for v and calculate v=2 r/T T=2 r/v = 0.56 s Speed equals circumference divided by period t = 30 T = 16.9 s Time = # rev x seconds/rev 3. A brass ball with a mass of 120 grams is suspended from a string that is 60.0 cm long. The ball is given a push and it moves in a horizontal circle. A satellite of mass 1000 kg is in circular orbit about Earth. The radius of the orbit of the satellite is equal to two times the radius of Earth. (a) How far away is the satellite? (b) Find the kinetic, potential, and total energies of the satellite. A hypothetical planet has a radius 2.3 times that of Earth. but has the same mass. What is the acceleration due to gravity near its surface? .Interested in T...Earth radius (denoted by the symbol R 🜨 or by ) is the distance from the center of Earth to a point on or near its surface. Approximating the figure of Earth by an Earth spheroid, the radius ranges from a maximum of nearly 6,378 km (3,963 mi) (equatorial radius, denoted a) to a minimum of nearly 6,357 km (3,950 mi) (polar radius, denoted b). One, a main sequence A star with a mass of twice the mass of the Sun, lies at a distance of 100 light years, and has a surface temperature of 9000 K and a radius of 106 km. The second, a red giant with mass equal to the mass of the Sun, has a surface temperature of 3000 K and a radius 100 times larger than that of the A star. a.Use the standard values of g, R E R E, and Equation 13.2 to find the mass of Earth. Estimate the value of g on the Moon. Use the fact that the Moon has a radius of about 1700 km (a value of this accuracy was determined many centuries ago) and assume it has the same average density as Earth, 5500 kg/m 3 5500 kg/m 3. StrategyOr put another way it is 4/9 that of the Earth's, or 44% of the Earth's gravity. Even though the mass of the planet is greater, the gravity goes down! 4. You travel to the planet Mirana, which has a mass that is 2 times smaller than the Earth's and a radius that is 4 times smaller. How does the force of gravity on Mirana compare to that of the ...However, because Jupiter's radius balloons to roughly 11 times as large as Earth's, its gravitational force drops off by a factor of 1/112 at its surface (assuming you could find a way to stand on ...In terms of surface area, Jupiter is 121.9 times bigger than the Earth. That's how many Earths could be flattened out to cover the surface of Jupiter. Jupiter has 317.8 times the mass of the Earth.Dec 11, 2012 · r / m) = 8.9 m/s Solve for v and calculate v=2 r/T T=2 r/v = 0.56 s Speed equals circumference divided by period t = 30 T = 16.9 s Time = # rev x seconds/rev 3. A brass ball with a mass of 120 grams is suspended from a string that is 60.0 cm long. The ball is given a push and it moves in a horizontal circle. arduino mkr gsm 1400 tutorialEarth on the Moon is F, the magnitude of the gravitational force of the Moon on Earth is 4. 5. 6. Date: Earth's mass is approximately 81 times the mass of the Moon. If Earth exerts a gravitational force of magnitude F on the Moon, the maonitude of the gravitational force of the Moon on Earth is 2. 3. c. smaller than F equal to F B. larger than F [email protected] there\'s something seriously wrong with your calc. cube root of 4.5 is only 1.65, so it has 1.65 times earth radius, and as it turns out therefore 1.65 times the force of gravity at the surface.Title: Microsoft PowerPoint - Chapter13 [Compatibility Mode] Author: Mukesh Dhamala Created Date: 4/7/2011 9:10:52 AMThis shorter time would decrease the probability of observing such a star by ~1/4. On the other hand, lower-mass 55M ⊙ stars may be roughly four times as numerous as 100M ⊙ stars, depending on ...Weight, mass and gravitational field strength The weight of an object may be thought of as acting at a single point called its centre of mass . Depending on the object's shape, its centre of mass ...A hypothetical planet has a mass 1.55 times that of Earth, but the same radius. What is 'g' near...4. An iron sphere of mass 10 kg has the same diameter as an aluminium sphere of mass is 3.5 kg. Both spheres are dropped simultaneously from a tower. When they are 10 m above the ground, they have the same : (a) Acceleration (b) Momentum (c) Potential energy (d) Kinetic energy. Solution (a) Acceleration15. A hypothetical planet has a mass of four times that of the Earth and radius of twice that of the Earth? What is the acceleration due to gravity on the planet in terms of the acceleration on the Earth? A. g B. C. D.2g E.The mass of the Earth is 5.98×10245.98×1024 kg, and the radius of the Earth is 6.38×1066.38×106 m. arrow_forward The Martian satellite Phobos travels in an approximately circular orbit of radius 9.4* 10^6 m with a period of 7 h 39 min. Calculate the mass of Mars from this information.Doubling the mass of the Earth would double your weight, since gravitational force is directly proportional to mass, but doubling the radius (which doubles if the diameter doubles) would decrease your weight by a factor of 1/4, since gravitational force is inversely proportional to the square of the radius.the mass of Vesta in units of the mass of the Earth the volume of Pluto in units of the volume of the Earth a) the mass of Jupiter: M Jupiter = 1.90 x 10 27 gm x (1 M earth / 5.98 x 10 24 gm) = 317.8 M earth b) the diameter of Saturn: D saturn = 120,660 km x (1 D earth / 12,756 km) = 9.46 D earth c) the mass of the Moon:hill cipher decoderA satellite of mass 1000 kg is in circular orbit about Earth. The radius of the orbit of the satellite is equal to two times the radius of Earth. (a) How far away is the satellite? (b) Find the kinetic, potential, and total energies of the satellite.Let us consider a planet such that mass of the planet is equal to 4 times the mass of the earth. M p = 4M. Radius of the planet is equal to 3 times the radius of earth. R e = 3 R. Then, acceleration due to gravity on this planet (g p) is. g p = G ∗ (4 M) 3 R 2 = 4 9 G M R 2.....(2) Dividing equation (2) by equation (1), we get. g p g e = 4 9 ...A system consists of a disk of mass 2.0 kg and radius 50 cm upon which is mounted an annular cylinder of mass 1.0 kg with inner radius 20 cm and outer radius 30 cm (see below). The system rotates about an axis through the center of the disk and annular cylinder at 10 rev/s.11. A year on Mars equals 1.88 Earth years. If the earth is 1.5x10 11 m from the sun, use Kepler's third law to determine how far Mars is from the sun. T M T E 2 = r M r E 3 r M 3 = T M 2r E 3 T E 2 = ( )1.88yrs2(1.5x1011m)3 (1yr)2 r M =2.28x1011m 12. A hypothetical planet has a radius 2.5 times that of Earth, but has the same mass. What is the ...If earth has a mass 9 times and radius twice of a planetvl Mars calculate the minimum velocity required by a rocket to pull out of gravitational force of mars. Take the escape velocity on the surface of earth to be 11.2 km/s 2 See answers Advertisement oohamaruri Hope this is right. You need to check once. Advertisement yadavyash596The radius of orbit indicates the distance which the satellite is from the center of the earth. Now that the radius of orbit has been found, the height above the earth can be calculated. Since the earth's surface is 6.37 x 10 6 m from its center (that's the radius of the earth), the satellite must be a height of. 4.23 x 10 7 m - 6.37 x 10 6 m ... Jul 09, 2019 · If the earth has a mass nine times and radius twice that of the planet Mars. Given escape speed on the surface of Earth is 11.2 km s^(-1). asked Oct 31, 2021 in Physics by HimanshuJain ( 91.0k points) the mass of Vesta in units of the mass of the Earth the volume of Pluto in units of the volume of the Earth a) the mass of Jupiter: M Jupiter = 1.90 x 10 27 gm x (1 M earth / 5.98 x 10 24 gm) = 317.8 M earth b) the diameter of Saturn: D saturn = 120,660 km x (1 D earth / 12,756 km) = 9.46 D earth c) the mass of the Moon:Mar 29, 2022 · Just slightly larger than nearby Venus, Earth is the biggest of the four planets closest to the Sun, all of which are made of rock and metal. The name Earth is at least 1,000 years old. All of the planets, except for Earth, were named after Greek and Roman gods and goddesses. However, the name Earth is a Germanic word, which simply means “the ... Both of these values are very close to the accepted modern values for the Earth's circumference and radius, 40,070 km and 6378 km respectively, which have since been measured by orbiting spacecraft. The diameter of a circle is twice the radius, giving us a diameter for Earth of 12,756 km. Note: The Earth is almost, but not quite, a perfect sphere.where g = gravity, G is the universal constant, M is mass, and r is the radius of the planet. earths mass is about 5.937e24 kg. and radius is about 6.371e6 km keep in mind that the earth is not ...Jul 06, 2021 · Earth's polar radius is 3,950 miles (6,356 km) — a difference of 13 miles (22 km). Using those measurements, the equatorial circumference of Earth is about 24,901 miles (40,075 km). If earth has amass 9 times and radius 4 times than that of a planet 'P'. Calculate the escape velocity of the planet P if its value on earth is 11.2 km/s. Kranav Sharma, Meritnation Expert added an answer, on 14/12/13 The escape velocity is given as v= [2GM/R] 1/2 now, for earth v e = [2GM e /R e] 1/2 or v e = 11.2km/s for planetanimal human picrew0.4MR2 for a solid sphere and g = 9.8 m/s2) a. 4.7 m/s b. 4.1 m/s c. 3.4 m/s d. 2.4 m/s 24. A solid cylinder of mass 3.0 kg and radius 0.2 m starts from rest at the top of a ramp, inclined 15°, and rolls to the bottom without slipping. (For a cylinder I = 0.5MR2) The upper end of the ramp is 1.2 m higher than the lower end.The mean radius of the orbit of a satellite is 4 times as great as that of the parking orbit of the earth. Then its period of revolution around the earth is 643050242weigh 160 lbs on Earth, you'd weigh only 160 × ¼ = 40 pounds on the hypothetical planet. 45. If the hypothetical star's mass is 4 times greater than the mass of the Sun, then the factor (m 1 + m 2) in Newton's form of Kepler's 3 rd law (page 86) is 4 times greater, too, since the mass of the Earth compared to the mass of the Sun (or to the ..., and to find the mass of Earth. Estimate the value of g on the Moon. Use the fact that the Moon has a radius of about 1700 km (a value of this accuracy was determined many centuries ago) and assume it has the same average density as Earth, . Strategy. With the known values of g and , we can use to find . For the Moon, we use the assumption of ...Weight, mass and gravitational field strength The weight of an object may be thought of as acting at a single point called its centre of mass . Depending on the object's shape, its centre of mass ...Explain what information you would use to find the mass of the planet and how the mass could be determined. The Earth has a radius of 6400 kilometers and a mass of 6.0 × 10 24 kilograms. What is its density? A planet has a rocky surface of material with density 3 (relative to the density of water) and an interior of material with density 2.5.The sun has a mass of 1.99x10 30 kg so this neutron star has a mass five times that: 5(1.99x10 30 kg) = 9.95x10 30 kg Its radius is 10 km or 10,000 m Now we just plug into our formulaAn astronaut of mass $$\text{70}$$ $$\text{kg}$$ on Earth lands on a planet which has half the Earth's radius and twice its mass. Calculate the magnitude of the force of gravity which is exerted on him on the planet.Figure 13.12 A satellite of mass m orbiting at radius r from the center of Earth. The gravitational force supplies the centripetal acceleration. We solve for the speed of the orbit, noting that m cancels, to get the orbital speed. Consistent with what we saw in (Figure) and (Figure), m does not appear in (Figure). Dec 11, 2012 · r / m) = 8.9 m/s Solve for v and calculate v=2 r/T T=2 r/v = 0.56 s Speed equals circumference divided by period t = 30 T = 16.9 s Time = # rev x seconds/rev 3. A brass ball with a mass of 120 grams is suspended from a string that is 60.0 cm long. The ball is given a push and it moves in a horizontal circle. For example, Uranus is about 15 times more massive than Earth and its radius is about 4 times Earth's. What is its escape velocity? The 15 times bigger mass means V is 15 = 3.87 times larger. The 4 times larger radius means that V is 4 = 2 times smaller. Combining the scaling factors gives us that V is 3.87/2 = 1.94 times larger or V = 1.94x11 ...13.2 Gravitation Near Earth's Surface. 20. (a) Calculate Earth's mass given the acceleration due to gravity at the North Pole is measured to be 9.832m/s29.832m/s2 and the radius of the Earth at the pole is 6356 km. (b) Compare this with the NASA's Earth Fact Sheet value of 5.9726×1024kg5.9726×1024kg. 21.To find weight when you already know the mass, use the formula weight = mass times gravitational acceleration. Remember that on the surface of the earth, gravitational acceleration is always 9.8 m/s^2, so simply plug in the mass and multiply it by 9.8 to get the weight in newtons.For example, Uranus is about 15 times more massive than Earth and its radius is about 4 times Earth's. What is its escape velocity? The 15 times bigger mass means V is 15 = 3.87 times larger. The 4 times larger radius means that V is 4 = 2 times smaller. Combining the scaling factors gives us that V is 3.87/2 = 1.94 times larger or V = 1.94x11 ...east west composer cloud -fc